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/* Convert a `struct tm' to a time_t value.
Copyright (C) 1993, 94, 95, 96, 97, 98, 99 Free Software Foundation, Inc.
This file is part of the GNU C Library.
Contributed by Paul Eggert (eggert@twinsun.com).
The GNU C Library is free software; you can redistribute it and/or
modify it under the terms of the GNU Lesser General Public
License as published by the Free Software Foundation; either
version 2.1 of the License, or (at your option) any later version.
The GNU C Library is distributed in the hope that it will be useful,
but WITHOUT ANY WARRANTY; without even the implied warranty of
MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
Lesser General Public License for more details.
You should have received a copy of the GNU Lesser General Public
License along with the GNU C Library; if not, write to the Free
Software Foundation, Inc., 59 Temple Place, Suite 330, Boston, MA
02111-1307 USA. */
/* Define this to have a standalone program to test this implementation of
mktime. */
#include <features.h>
/* Assume that leap seconds are not possible */
#undef LEAP_SECONDS_POSSIBLE
#include <sys/types.h> /* Some systems define `time_t' here. */
#include <time.h>
#include <limits.h>
#if 0
#ifndef CHAR_BIT
# define CHAR_BIT 8
#endif
/* The extra casts work around common compiler bugs. */
#define TYPE_SIGNED(t) (! ((t) 0 < (t) -1))
/* The outer cast is needed to work around a bug in Cray C 5.0.3.0.
It is necessary at least when t == time_t. */
#define TYPE_MINIMUM(t) ((t) (TYPE_SIGNED (t) \
? ~ (t) 0 << (sizeof (t) * CHAR_BIT - 1) : (t) 0))
#define TYPE_MAXIMUM(t) ((t) (~ (t) 0 - TYPE_MINIMUM (t)))
#ifndef INT_MIN
# define INT_MIN TYPE_MINIMUM (int)
#endif
#ifndef INT_MAX
# define INT_MAX TYPE_MAXIMUM (int)
#endif
#ifndef TIME_T_MIN
# define TIME_T_MIN TYPE_MINIMUM (time_t)
#endif
#ifndef TIME_T_MAX
# define TIME_T_MAX TYPE_MAXIMUM (time_t)
#endif
#define TM_YEAR_BASE 1900
#define EPOCH_YEAR 1970
/* How many days come before each month (0-12). */
extern const unsigned short int __mon_yday[2][13];
/* Yield the difference between (YEAR-YDAY HOUR:MIN:SEC) and (*TP),
measured in seconds, ignoring leap seconds.
YEAR uses the same numbering as TM->tm_year.
All values are in range, except possibly YEAR.
If TP is null, return a nonzero value.
If overflow occurs, yield the low order bits of the correct answer. */
static time_t
__ydhms_tm_diff (int year, int yday, int hour, int min, int sec,
const struct tm *tp)
{
if (!tp)
return 1;
else
{
/* Compute intervening leap days correctly even if year is negative.
Take care to avoid int overflow. time_t overflow is OK, since
only the low order bits of the correct time_t answer are needed.
Don't convert to time_t until after all divisions are done, since
time_t might be unsigned. */
int a4 = (year >> 2) + (TM_YEAR_BASE >> 2) - ! (year & 3);
int b4 = (tp->tm_year >> 2) + (TM_YEAR_BASE >> 2) - ! (tp->tm_year & 3);
int a100 = a4 / 25 - (a4 % 25 < 0);
int b100 = b4 / 25 - (b4 % 25 < 0);
int a400 = a100 >> 2;
int b400 = b100 >> 2;
int intervening_leap_days = (a4 - b4) - (a100 - b100) + (a400 - b400);
time_t years = year - (time_t) tp->tm_year;
time_t days = (365 * years + intervening_leap_days
+ (yday - tp->tm_yday));
return (60 * (60 * (24 * days + (hour - tp->tm_hour))
+ (min - tp->tm_min))
+ (sec - tp->tm_sec));
}
}
/* Use CONVERT to convert *T to a broken down time in *TP.
If *T is out of range for conversion, adjust it so that
it is the nearest in-range value and then convert that. */
static struct tm *
__ranged_convert (struct tm *(*convert) (const time_t *, struct tm *),
time_t *t, struct tm *tp)
{
struct tm *r;
if (! (r = (*convert) (t, tp)) && *t)
{
time_t bad = *t;
time_t ok = 0;
struct tm tm;
/* BAD is a known unconvertible time_t, and OK is a known good one.
Use binary search to narrow the range between BAD and OK until
they differ by 1. */
while (bad != ok + (bad < 0 ? -1 : 1))
{
time_t mid = *t = (bad < 0
? bad + ((ok - bad) >> 1)
: ok + ((bad - ok) >> 1));
if ((r = (*convert) (t, tp)))
{
tm = *r;
ok = mid;
}
else
bad = mid;
}
if (!r && ok)
{
/* The last conversion attempt failed;
revert to the most recent successful attempt. */
*t = ok;
*tp = tm;
r = tp;
}
}
return r;
}
/* Convert *TP to a time_t value, inverting
the monotonic and mostly-unit-linear conversion function CONVERT.
Use *OFFSET to keep track of a guess at the offset of the result,
compared to what the result would be for UTC without leap seconds.
If *OFFSET's guess is correct, only one CONVERT call is needed. */
time_t __mktime_internal (struct tm *tp,
struct tm *(*convert) (const time_t *, struct tm *), time_t *offset)
{
time_t t, dt, t0, t1, t2;
struct tm tm;
/* The maximum number of probes (calls to CONVERT) should be enough
to handle any combinations of time zone rule changes, solar time,
leap seconds, and oscillations around a spring-forward gap.
POSIX.1 prohibits leap seconds, but some hosts have them anyway. */
int remaining_probes = 6;
/* Time requested. Copy it in case CONVERT modifies *TP; this can
occur if TP is localtime's returned value and CONVERT is localtime. */
int sec = tp->tm_sec;
int min = tp->tm_min;
int hour = tp->tm_hour;
int mday = tp->tm_mday;
int mon = tp->tm_mon;
int year_requested = tp->tm_year;
int isdst = tp->tm_isdst;
/* Ensure that mon is in range, and set year accordingly. */
int mon_remainder = mon % 12;
int negative_mon_remainder = mon_remainder < 0;
int mon_years = mon / 12 - negative_mon_remainder;
int year = year_requested + mon_years;
/* The other values need not be in range:
the remaining code handles minor overflows correctly,
assuming int and time_t arithmetic wraps around.
Major overflows are caught at the end. */
/* Calculate day of year from year, month, and day of month.
The result need not be in range. */
int yday = ((__mon_yday[__isleap (year + TM_YEAR_BASE)]
[mon_remainder + 12 * negative_mon_remainder])
+ mday - 1);
int sec_requested = sec;
#if LEAP_SECONDS_POSSIBLE
/* Handle out-of-range seconds specially,
since __ydhms_tm_diff assumes every minute has 60 seconds. */
if (sec < 0)
sec = 0;
if (59 < sec)
sec = 59;
#endif
/* Invert CONVERT by probing. First assume the same offset as last time.
Then repeatedly use the error to improve the guess. */
tm.tm_year = EPOCH_YEAR - TM_YEAR_BASE;
tm.tm_yday = tm.tm_hour = tm.tm_min = tm.tm_sec = 0;
t0 = __ydhms_tm_diff (year, yday, hour, min, sec, &tm);
for (t = t1 = t2 = t0 + *offset;
(dt = __ydhms_tm_diff (year, yday, hour, min, sec,
__ranged_convert (convert, &t, &tm)));
t1 = t2, t2 = t, t += dt)
if (t == t1 && t != t2
&& (isdst < 0 || tm.tm_isdst < 0
|| (isdst != 0) != (tm.tm_isdst != 0)))
/* We can't possibly find a match, as we are oscillating
between two values. The requested time probably falls
within a spring-forward gap of size DT. Follow the common
practice in this case, which is to return a time that is DT
away from the requested time, preferring a time whose
tm_isdst differs from the requested value. In practice,
this is more useful than returning -1. */
break;
else if (--remaining_probes == 0)
return -1;
/* If we have a match, check whether tm.tm_isdst has the requested
value, if any. */
if (dt == 0 && isdst != tm.tm_isdst && 0 <= isdst && 0 <= tm.tm_isdst)
{
/* tm.tm_isdst has the wrong value. Look for a neighboring
time with the right value, and use its UTC offset.
Heuristic: probe the previous three calendar quarters (approximately),
looking for the desired isdst. This isn't perfect,
but it's good enough in practice. */
int quarter = 7889238; /* seconds per average 1/4 Gregorian year */
int i;
/* If we're too close to the time_t limit, look in future quarters. */
if (t < TIME_T_MIN + 3 * quarter)
quarter = -quarter;
for (i = 1; i <= 3; i++)
{
time_t ot = t - i * quarter;
struct tm otm;
__ranged_convert (convert, &ot, &otm);
if (otm.tm_isdst == isdst)
{
/* We found the desired tm_isdst.
Extrapolate back to the desired time. */
t = ot + __ydhms_tm_diff (year, yday, hour, min, sec, &otm);
__ranged_convert (convert, &t, &tm);
break;
}
}
}
*offset = t - t0;
#if LEAP_SECONDS_POSSIBLE
if (sec_requested != tm.tm_sec)
{
/* Adjust time to reflect the tm_sec requested, not the normalized value.
Also, repair any damage from a false match due to a leap second. */
t += sec_requested - sec + (sec == 0 && tm.tm_sec == 60);
if (! (*convert) (&t, &tm))
return -1;
}
#endif
if (TIME_T_MAX / INT_MAX / 366 / 24 / 60 / 60 < 3)
{
/* time_t isn't large enough to rule out overflows in __ydhms_tm_diff,
so check for major overflows. A gross check suffices,
since if t has overflowed, it is off by a multiple of
TIME_T_MAX - TIME_T_MIN + 1. So ignore any component of
the difference that is bounded by a small value. */
double dyear = (double) year_requested + mon_years - tm.tm_year;
double dday = 366 * dyear + mday;
double dsec = 60 * (60 * (24 * dday + hour) + min) + sec_requested;
/* On Irix4.0.5 cc, dividing TIME_T_MIN by 3 does not produce
correct results, ie., it erroneously gives a positive value
of 715827882. Setting a variable first then doing math on it
seems to work. (ghazi@caip.rutgers.edu) */
const time_t time_t_max = TIME_T_MAX;
const time_t time_t_min = TIME_T_MIN;
if (time_t_max / 3 - time_t_min / 3 < (dsec < 0 ? - dsec : dsec))
return -1;
}
*tp = tm;
return t;
}
/* Convert *TP to a time_t value. */
time_t mktime (struct tm *tp)
{
static time_t localtime_offset;
/* POSIX.1 8.1.1 requires that whenever mktime() is called, the
time zone names contained in the external variable `tzname' shall
be set as if the tzset() function had been called. */
tzset ();
return __mktime_internal (tp, localtime_r, &localtime_offset);
}
#else
/* Convert *TP to a time_t value. */
time_t mktime (struct tm *tp)
{
time_t m_secs=tp->tm_min*60;
time_t h_secs=tp->tm_hour*3600;
time_t d_secs=tp->tm_yday*86400;
time_t y_secs=(tp->tm_year-70)*31536000;
time_t l_secs1=((tp->tm_year-69)/4)*86400;
time_t l_secs2=((tp->tm_year-1)/100)*86400;
time_t l_secs3=((tp->tm_year+299)/400)*86400;
return m_secs+h_secs+d_secs+y_secs+l_secs1-l_secs2+l_secs3+tp->tm_gmtoff;
}
#endif
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