From 1077fa4d772832f77a677ce7fb7c2d513b959e3f Mon Sep 17 00:00:00 2001
From: Eric Andersen <andersen@codepoet.org>
Date: Thu, 10 May 2001 00:40:28 +0000
Subject: uClibc now has a math library.  muahahahaha!  -Erik

---
 libm/double/minv.c | 61 ++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 61 insertions(+)
 create mode 100644 libm/double/minv.c

(limited to 'libm/double/minv.c')

diff --git a/libm/double/minv.c b/libm/double/minv.c
new file mode 100644
index 000000000..df788fecf
--- /dev/null
+++ b/libm/double/minv.c
@@ -0,0 +1,61 @@
+/*							minv.c
+ *
+ *	Matrix inversion
+ *
+ *
+ *
+ * SYNOPSIS:
+ *
+ * int n, errcod;
+ * double A[n*n], X[n*n];
+ * double B[n];
+ * int IPS[n];
+ * int minv();
+ *
+ * errcod = minv( A, X, n, B, IPS );
+ *
+ *
+ *
+ * DESCRIPTION:
+ *
+ * Finds the inverse of the n by n matrix A.  The result goes
+ * to X.   B and IPS are scratch pad arrays of length n.
+ * The contents of matrix A are destroyed.
+ *
+ * The routine returns nonzero on error; error messages are printed
+ * by subroutine simq().
+ *
+ */
+
+minv( A, X, n, B, IPS )
+double A[], X[];
+int n;
+double B[];
+int IPS[];
+{
+double *pX;
+int i, j, k;
+
+for( i=1; i<n; i++ )
+	B[i] = 0.0;
+B[0] = 1.0;
+/* Reduce the matrix and solve for first right hand side vector */
+pX = X;
+k = simq( A, B, pX, n, 1, IPS );
+if( k )
+	return(-1);
+/* Solve for the remaining right hand side vectors */
+for( i=1; i<n; i++ )
+	{
+	B[i-1] = 0.0;
+	B[i] = 1.0;
+	pX += n;
+	k = simq( A, B, pX, n, -1, IPS );
+	if( k )
+		return(-1);
+	}
+/* Transpose the array of solution vectors */
+mtransp( n, X, X );
+return(0);
+}
+
-- 
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